JEE Main 2024 (Online) 30th January Evening ShiftQuestion 1
Let $\vec{a}$ and $\vec{b}$ be two vectors such that $|\vec{b}|=1$ and $|\vec{b}\times\vec{a}|=2$. Then $\left|(\vec{b}\times\vec{a})-\vec{b}\right|^{2}$ is equal to
Vector Algebra
Solution
$\vec b\times\vec a\perp\vec b$, so $\vec b\cdot(\vec b\times\vec a)=0$. $|(\vec b\times\vec a)-\vec b|^2=|\vec b\times\vec a|^2+|\vec b|^2=4+1=5$. Option (D).