JEE Advanced 2023 Paper 1Question 1
Consider the given data with frequency distribution
$$\begin{array}{c|cccccc} x_i & 3 & 8 & 11 & 10 & 5 & 4\\ \hline f_i & 5 & 2 & 3 & 2 & 4 & 4\end{array}$$
Match each entry in List-I to the correct entries in List-II.
List-I
(P) The mean of the above data is
(Q) The median of the above data is
(R) The mean deviation about the mean of the above data is
(S) The mean deviation about the median of the above data is
List-II
(1) 2.5
(2) 5
(3) 6
(4) 2.7
(5) 2.4
The correct option is:
Statistics
Solution
$N=20$, $\sum fx=120$, mean $6$. Sorted, the 10th and 11th values are both $5$, median $5$. $\sum f|x-6|=54$ gives $2.7$; $\sum f|x-5|=48$ gives $2.4$. So P-3, Q-2, R-4, S-5.