AIEEE 2005 (Offline)Question 1
If in a frequency distribution, the mean and median are $21$ and $22$ respectively, then its mode is approximately :
Statistics
Solution
Mode $\approx3\,\text{median}-2\,\text{mean}=66-42=24$.Solution
Mode $\approx3\,\text{median}-2\,\text{mean}=66-42=24$.