Sets, Relations and Function: Let A=\x:|x^2-10|le6\ and B=\x:|x-2|>1\ . Then | JEE Main 2026

JEE Main 2026 (Online) 21st January Evening ShiftQuestion 1

Let $A=\{x:|x^2-10|\le6\}$ and $B=\{x:|x-2|>1\}$. Then

Sets, Relations and Function

$A\cap B=[-4,-2]\cup[3,4]$$A\cup B=(-\infty,1]\cup(2,\infty)$$B-A=(-\infty,-4)\cup(-2,1)\cup(4,\infty)$✓ Correct answer$A-B=[2,3)$

Solution

$A=[-4,-2]\cup[2,4]$, $B=(-\infty,1)\cup(3,\infty)$. $B-A=(-\infty,-4)\cup(-2,1)\cup(4,\infty)$ matches; the others fail ($A\cap B=[-4,-2]\cup(3,4]$, $A-B=[2,3]$).

Sets, Relations and Function - JEE Mathematics question (JEE Main 2026 (Online) 21st January Evening Shift)

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