JEE Main 2024 (Online) 29th January Evening ShiftQuestion 1
An integer is chosen at random from the integers $1,2,3,\ldots,50$. The probability that the chosen integer is a multiple of at least one of $4$, $6$ and $7$ is
Probability
Solution
Multiples: of $4$: $12$, of $6$: $8$, of $7$: $7$; of $12$: $4$, of $28$: $1$, of $42$: $1$, of $84$: $0$. Union $=12+8+7-4-1-1=21$, so $\frac{21}{50}$.