AIEEE 2010 (Offline)Question 1
The line $L$ given by $\frac x5+\frac yb=1$ passes through the point $(13,32)$. The line $K$ is parallel to $L$ and has the equation $\frac xc+\frac y3=1$. Then the distance between $L$ and $K$ is :
Points and Straight Lines
Solution
$\frac{13}5+\frac{32}b=1\Rightarrow b=-20$, so $L:4x-y=20$; $K$ parallel with $y$-intercept $3$: $4x-y+3=0$. Distance $=\frac{23}{\sqrt{17}}$.