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Inverse Trigonometric Functions - JEE Mathematics question (JEE Main 2019 (Online) 12th January Morning Shift)

JEE Main 2019 (Online) 12th January Morning ShiftQuestion 1
Considering only the principal values of inverse functions, the set $A=\left\{x\ge0:\tan^{-1}(2x)+\tan^{-1}(3x)=\frac\pi4\right\}$
Inverse Trigonometric Functions
Options for question 1, choose one

Solution

$\frac{5x}{1-6x^2}=1\Rightarrow6x^2+5x-1=0$, $x=\frac16$ or $x=-1$; only $x=\frac16\ge0$ works. $A$ is a singleton.

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