AIEEE 2004 (Offline)Question 1
The domain of the function $f(x)=\frac{\sin^{-1}(x-3)}{\sqrt{9-x^{2}}}$ is
Inverse Trigonometric Functions
Solution
Need $-1\le x-3\le1$, i.e. $2\le x\le4$, and $9-x^2>0$, i.e. $-3<x<3$. Domain $[2,3)$.Inverse Trigonometric Functions - JEE Mathematics question (AIEEE 2004 (Offline))
More from Inverse Trigonometric Functions
- Let g(x)=f(x)+f(1-x) and f''(x)>0 , xin(0,1) . If g is decreasing in the interval (0,alpha) and increasing…
- Considering only the principal values of the inverse trigonometric functions, the value of tan (sin^-1…
- For ninmathbbN , if cot^-13+cot^-14+cot^-15+cot^-1n=(pi)/(4) , then n is equal to \_\_\_\_\_\_ .
- Prove that costan^-1sincot^-1x=sqrtdfracx^2+1x^2+2 .
- If (pi)/(2)le xle(3pi)/(4) , then cos^-1 ((12)/(13)cos x+(5)/(13)sin x ) is equal to
- If the sum of all the solutions of tan^-1 (frac2x1-x^2 )+cot^-1 (frac1-x^22x )=fracpi3,\ -1<x<1,\ xneq0 , is…
- Let tan^-1(x)in (-(pi)/(2),(pi)/(2) ) , for xinmathbbR . Then the number of real solutions of the equation…
- tan (2tan^-1frac15+sec^-1(sqrt5)/(2)+2tan^-1frac18 ) is equal to :