JEE Main 2019 (Online) 12th April Morning ShiftQuestion 1
The integral $\int\frac{2x^3-1}{x^4+x}dx$ is equal to
Indefinite Integration
Solution
Concept. After dividing by $x^2$, the numerator is the derivative of the denominator. Formulas used. (1) $\int\dfrac{h'(x)}{h(x)}\,dx=\ln|h(x)|+C$Step 1 - Divide by $x^2$. $$\frac{2x^3-1}{x^4+x}=\frac{2x-x^{-2}}{x^2+x^{-1}}.$$ Here $\dfrac{d}{dx}\left(x^2+\dfrac1x\right)=2x-\dfrac1{x^2}$. Step 2 - Use (1). $$\int=\ln\left|x^2+\frac1x\right|+C=\ln\left|\frac{x^3+1}{x}\right|+C.$$ Answer: (C)