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Yukti Vault

Complex Numbers - JEE Mathematics question (IIT-JEE 1998)

IIT-JEE 1998Question 1
If $\omega$ is an imaginary cube root of unity, then $(1+\omega-\omega^{2})^{7}$ equals
Complex Numbers
Options for question 1, one or more may be correct

More than one option may be correct.

Solution

$1+\omega=-\omega^2$, so $1+\omega-\omega^2=-2\omega^2$. Then $(-2\omega^2)^7=-128\omega^{14}=-128\omega^2$.

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