JEE Main 2021 (Online) 27th July Evening ShiftQuestion 1
The area of the region bounded by $y-x=2$ and $x^2=y$ is equal to :
Application of Integrals
Solution
$x^2=x+2\Rightarrow x=-1,2$. $A=\int_{-1}^2(x+2-x^2)dx=\left[\frac{x^2}2+2x-\frac{x^3}3\right]_{-1}^2=\frac{10}3-(-\frac76)=\frac92$. Option (C).