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Application of Integrals - JEE Mathematics question (JEE Main 2019 (Online) 10th April Evening Shift)

JEE Main 2019 (Online) 10th April Evening ShiftQuestion 1
The area (in sq. units) of the region bounded by the curves $y=2^{x}$ and $y=x+1$, in the first quadrant is
Application of Integrals
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Solution

Curves meet at $x=0,1$ with $x+1\ge2^x$ between. Area $=\int_0^1(x+1-2^x)dx=\frac32-\frac1{\ln2}$.

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