JEE Main 2026 (Online) 5th April Morning ShiftQuestion 1
The square of the distance of the point $P(5,6,7)$ from the line $\frac{x-2}{2}=\frac{y-5}{3}=\frac{z-2}{4}$ is equal to :
3D Geometry
Solution
$\vec{AP}=(3,1,5)$, $|\vec{AP}|^2=35$, $\vec{AP}\cdot\vec d=29$, $|\vec d|^2=29$. Distance$^2=35-\frac{29^2}{29}=6$.