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3D Geometry - JEE Mathematics question (JEE Main 2023 (Online) 29th January Evening Shift)

JEE Main 2023 (Online) 29th January Evening ShiftQuestion 1
If the lines $\frac{x-1}{1}=\frac{y-2}{2}=\frac{z+3}{1}$ and $\frac{x-a}{2}=\frac{y+2}{3}=\frac{z-3}{1}$ intersects at the point $P$, then the distance of the point $P$ from the plane $z=a$ is :
3D Geometry
Options for question 1, choose one

Solution

Equate points: $2+2t=-2+3s$, $-3+t=3+s$ give $s=16,t=22$; then $1+t=a+2s$ gives $a=-9$. $P$ has $z=19$, distance from $z=-9$ is $28$.

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