JEE Main 2021 (Online) 20th July Evening ShiftQuestion 7496
For $p>0$, a vector $\vec{v}_2=2\hat{i}+(p+1)\hat{j}$ is obtained by rotating the vector $\vec{v}_1=\sqrt{3}p\,\hat{i}+\hat{j}$ by an angle $\theta$ about origin in counter clockwise direction. If $\tan\theta=\dfrac{\alpha\sqrt{3}-2}{4\sqrt{3}+3}$, then the value of $\alpha$ is equal to $\_\_\_\_\_\_\_\_$ .
Vector Algebra