AIEEE 2009 (Offline)Question 451
Let the line $\frac{x-2}{3}=\frac{y-1}{-5}=\frac{z+2}{2}$ lie in the plane $x+3y-\alpha z+\beta=0$. Then $(\alpha,\beta)$ equals
3D Geometry
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3D Geometry
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AIEEE 2010 (Offline)Question 452
Statement - 1 : The point $A(3,1,6)$ is the mirror image of the point $B(1,3,4)$ in the plane $x-y+z=5$. Statement - 2 : The plane $x-y+z=5$ bisects the line segment joining $A(3,1,6)$ and $B(1,3,4)$.
3D Geometry
AIEEE 2011 (Offline)Question 453
If the angle between the line $x=\frac{y-1}{2}=\frac{z-3}{\lambda}$ and the plane $x+2y+3z=4$ is $\cos^{-1}\left(\sqrt{\frac{5}{14}}\right)$, then $\lambda$ equals :
3D Geometry
JEE Main 2014 (Offline)Question 454
The image of the line $\frac{x-1}{3}=\frac{y-3}{1}=\frac{z-4}{-5}$ in the plane $2x-y+z+3=0$ is the line :
3D Geometry
JEE Main 2015 (Offline)Question 455
The equation of the plane containing the line $2x-5y+z=3$; $x+y+4z=5$, and parallel to the plane, $x+3y+6z=1$, is :
3D Geometry