JEE Maths PYQ Practice, chapter-wise

JEE Main 2025 (Online) 24th January Evening ShiftQuestion 436

Let $P$ be the image of the point $Q(7,-2,5)$ in the line $L:\dfrac{x-1}{2}=\dfrac{y+1}{3}=\dfrac{z}{4}$ and $R(5,p,q)$ be a point on $L$. Then the square of the area of $\triangle PQR$ is $\_\_\_\_\_\_\_\_$ .

3D Geometry

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JEE Main 2025 (Online) 28th January Evening ShiftQuestion 437

The square of the distance of the point $\left(\dfrac{15}{7},\dfrac{32}{7},7\right)$ from the line $\dfrac{x+1}{3}=\dfrac{y+3}{5}=\dfrac{z+5}{7}$ in the direction of the vector $\hat{i}+4\hat{j}+7\hat{k}$ is:

3D Geometry

$66$$54$$41$$44$

AIEEE 2002 (Offline)Question 438

The direction ratios of the normal to the plane through $(1,0,0)$, $(0,1,0)$ which makes an angle $\pi/4$ with the plane $x+y=3$ are :

3D Geometry

$1,\sqrt2,1$$1,1,\sqrt2$$1,1,2$$\sqrt2,1,1$

AIEEE 2002 (Offline)Question 439

A plane which passes through the point $(3,2,0)$ and the line $\frac{x-4}{1}=\frac{y-7}{5}=\frac{z-4}{4}$ is :

3D Geometry

$x-y+z=1$$x+y+z=5$$x+2y-z=1$$2x-y+z=5$

AIEEE 2003 (Offline)Question 440

Two systems of rectangular axes have the same origin. If a plane cuts them at distances $a,b,c$ and $a',b',c'$ from the origin, then

3D Geometry

$\frac1{a^2}+\frac1{b^2}+\frac1{c^2}-\frac1{a'^2}-\frac1{b'^2}-\frac1{c'^2}=0$$\frac1{a^2}+\frac1{b^2}+\frac1{c^2}+\frac1{a'^2}+\frac1{b'^2}+\frac1{c'^2}=0$$\frac1{a^2}+\frac1{b^2}-\frac1{c^2}+\frac1{a'^2}-\frac1{b'^2}-\frac1{c'^2}=0$$\frac1{a^2}-\frac1{b^2}-\frac1{c^2}+\frac1{a'^2}-\frac1{b'^2}-\frac1{c'^2}=0$