JEE Main 2026 (Online) 28th January Morning ShiftQuestion 376
If the distances of the point $(1,2,a)$ from the line $\frac{x-1}{1}=\frac y2=\frac{z-1}{1}$ along the lines $L_1:\frac{x-1}{3}=\frac{y-2}{4}=\frac{z-a}{b}$ and $L_2:\frac{x-1}{1}=\frac{y-2}{4}=\frac{z-a}{c}$ are equal, then $a+b+c$ is equal to :
3D Geometry