Skip to main content
Yukti Vault

JEE Mathematics / Practice

3D Geometry

Chapter overview and full question list

Showing 271-275 of 461 questions.

JEE Main 2016 (Online) 9th AprilQuestion 271
The shortest distance between the lines $\frac x2=\frac y2=\frac z1$ and $\frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}$, lies in the interval:
3D Geometry
Options for question 271, choose one
JEE Main 2019 (Online) 10th April Morning ShiftQuestion 272
If $Q(0,-1,-3)$ is the image of the point $P$ in the plane $3x-y+4z=2$ and $R$ is the point $(3,-1,-2)$, then the area (in sq. units) of $\triangle PQR$ is
3D Geometry
Options for question 272, choose one
JEE Main 2019 (Online) 9th January Evening ShiftQuestion 273
The equation of the plane containing the straight line $\frac x2=\frac y3=\frac z4$ and perpendicular to the plane containing the straight lines $\frac x3=\frac y4=\frac z2$ and $\frac x4=\frac y2=\frac z3$ is :
3D Geometry
Options for question 273, choose one
JEE Main 2019 (Online) 12th January Morning ShiftQuestion 274
A tetrahedron has vertices $P(1,2,1)$, $Q(2,1,3)$, $R(-1,1,2)$ and $O(0,0,0)$. The angle between the faces $OPQ$ and $PQR$ is
3D Geometry
Options for question 274, choose one
JEE Advanced 2019 Paper 2Question 275
Three lines $L_1: \vec r=\lambda\hat i,\ \lambda\in\mathbb{R}$, $L_2: \vec r=\hat k+\mu\hat j,\ \mu\in\mathbb{R}$ and $L_3: \vec r=\hat i+\hat j+v\hat k,\ v\in\mathbb{R}$ are given. For which point(s) $Q$ on $L_2$ can we find a point $P$ on $L_1$ and a point $R$ on $L_3$ so that $P, Q$ and $R$ are collinear?
3D Geometry
Options for question 275, one or more may be correct

More than one option may be correct.