JEE Main 2021 (Online) 18th March Evening ShiftQuestion 156
Let $P$ be a plane containing the line $\frac{x-1}{3}=\frac{y+6}{4}=\frac{z+5}{2}$ and parallel to the line $\frac{x-3}{4}=\frac{y-2}{-3}=\frac{z+5}{7}$. If the point $(1,-1,\alpha)$ lies on the plane $P$, then the value of $|5\alpha|$ is equal to $\_\_\_\_\_\_$ .
3D Geometry